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You are given two string arrays, queries and dictionary. All words in each array comprise of lowercase English letters and have the same length. In one edit you can take a word from queries, and change any letter in it to any other letter. Find all words from queries that, after a maximum of two edits, equal some word from dictionary. Return a list of all words from queries, that match with some word from dictionary after a maximum of two edits. Return the words in the same order they appear in queries.
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You are given two string arrays, queries and dictionary. All words in each array comprise of lowercase English letters and have the same length. In one edit you can take a word from queries, and change any letter in it to any other letter. Find all words from queries that, after a maximum of two edits, equal some word from dictionary. Return a list of all words from queries, that match with some word from dictionary after a maximum of two edits. Return the words in the same order they appear in queries.
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queries = ["word","note","ants","wood"], dictionary = ["wood","joke","moat"]
["word","note","wood"]
queries = ["yes"], dictionary = ["not"]
[]
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Solve Words Within Two Edits of Dictionary — You are given two string arrays, queries and dictionary. All words in each array...
Here's the optimal approach using Array:
Time: O(n) | Space: O(n)
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