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There are n people in a line queuing to buy tickets, where the 0th person is at the front of the line and the (n - 1)th person is at the back of the line. You are given a 0-indexed integer array tickets of length n where the number of tickets that the ith person would like to buy is tickets[i]. Each person takes exactly 1 second to buy a ticket. A person can only buy 1 ticket at a time and has to go back to the end of the line (which happens instantaneously) in order to buy more tickets. If a person does not have any tickets left to buy, the person will leave the line. Return the time taken for the person initially at position k (0-indexed) to finish buying tickets.
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There are n people in a line queuing to buy tickets, where the 0th person is at the front of the line and the (n - 1)th person is at the back of the line. You are given a 0-indexed integer array tickets of length n where the number of tickets that the ith person would like to buy is tickets[i]. Each person takes exactly 1 second to buy a ticket. A person can only buy 1 ticket at a time and has to go back to the end of the line (which happens instantaneously) in order to buy more tickets. If a person does not have any tickets left to buy, the person will leave the line. Return the time taken for the person initially at position k (0-indexed) to finish buying tickets.
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tickets = [2,3,2], k = 2
6
tickets = [5,1,1,1], k = 0
8
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Solve Time Needed to Buy Tickets — There are n people in a line queuing to buy tickets, where the 0th person is at ...
Here's the optimal approach using Array:
Time: O(n) | Space: O(n)
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