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There are n employees, each with a unique id from 0 to n - 1. You are given a 2D integer array logs where logs[i] = [idi, leaveTimei] where: Note that the ith task starts the moment right after the (i - 1)th task ends, and the 0th task starts at time 0. Return the id of the employee that worked the task with the longest time. If there is a tie between two or more employees, return the smallest id among them.
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There are n employees, each with a unique id from 0 to n - 1. You are given a 2D integer array logs where logs[i] = [idi, leaveTimei] where: Note that the ith task starts the moment right after the (i - 1)th task ends, and the 0th task starts at time 0. Return the id of the employee that worked the task with the longest time. If there is a tie between two or more employees, return the smallest id among them.
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n = 10, logs = [[0,3],[2,5],[0,9],[1,15]]
1
n = 26, logs = [[1,1],[3,7],[2,12],[7,17]]
3
n = 2, logs = [[0,10],[1,20]]
0
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Solve The Employee That Worked on the Longest Task — There are n employees, each with a unique id from 0 to n - 1. You are given a 2D...
Here's the optimal approach using Array:
Time: O(n) | Space: O(n)
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