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Given a string s and an integer k, reverse the first k characters for every 2k characters counting from the start of the string. If there are fewer than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse the first k characters and leave the other as original.
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Given a string s and an integer k, reverse the first k characters for every 2k characters counting from the start of the string. If there are fewer than k characters left, reverse all of them. If there are less than 2k but greater than or equal to k characters, then reverse the first k characters and leave the other as original.
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s = "abcdefg", k = 2
"bacdfeg"
s = "abcd", k = 2
"bacd"
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Solve Reverse String II — Given a string s and an integer k, reverse the first k characters for every 2k c...
Here's the optimal approach using Two Pointers:
Time: O(n) | Space: O(n)
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