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You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices. You must perform an operation shift(c, x), where c is a character and x is a digit, that returns the xth character after c. For every odd index i, you want to replace the digit s[i] with the result of the shift(s[i-1], s[i]) operation. Return s after replacing all digits. It is guaranteed that shift(s[i-1], s[i]) will never exceed 'z'. Note that shift(c, x) is not a preloaded function, but an operation to be implemented as part of the solution.
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You are given a 0-indexed string s that has lowercase English letters in its even indices and digits in its odd indices. You must perform an operation shift(c, x), where c is a character and x is a digit, that returns the xth character after c. For every odd index i, you want to replace the digit s[i] with the result of the shift(s[i-1], s[i]) operation. Return s after replacing all digits. It is guaranteed that shift(s[i-1], s[i]) will never exceed 'z'. Note that shift(c, x) is not a preloaded function, but an operation to be implemented as part of the solution.
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s = "a1c1e1"
"abcdef"
s = "a1b2c3d4e"
"abbdcfdhe"
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Solve Replace All Digits with Characters — You are given a 0-indexed string s that has lowercase English letters in its eve...
Here's the optimal approach using String:
Time: O(n) | Space: O(n)
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