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Given a circular integer array nums (i.e., the next element of nums[nums.length - 1] is nums[0]), return the next greater number for every element in nums. The next greater number of a number x is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. If it doesn't exist, return -1 for this number.
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Given a circular integer array nums (i.e., the next element of nums[nums.length - 1] is nums[0]), return the next greater number for every element in nums. The next greater number of a number x is the first greater number to its traversing-order next in the array, which means you could search circularly to find its next greater number. If it doesn't exist, return -1 for this number.
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nums = [1,2,1]
[2,-1,2]
nums = [1,2,3,4,3]
[2,3,4,-1,4]
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Solve Next Greater Element II — Given a circular integer array nums (i.e., the next element of nums[nums.length ...
Here's the optimal approach using Array:
Time: O(n) | Space: O(n)
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