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You are given the customer visit log of a shop represented by a 0-indexed string customers consisting only of characters 'N' and 'Y': If the shop closes at the jth hour (0 <= j <= n), the penalty is calculated as follows: Return the earliest hour at which the shop must be closed to incur a minimum penalty. Note that if a shop closes at the jth hour, it means the shop is closed at the hour j.
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You are given the customer visit log of a shop represented by a 0-indexed string customers consisting only of characters 'N' and 'Y': If the shop closes at the jth hour (0 <= j <= n), the penalty is calculated as follows: Return the earliest hour at which the shop must be closed to incur a minimum penalty. Note that if a shop closes at the jth hour, it means the shop is closed at the hour j.
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customers = "YYNY"
2
customers = "NNNNN"
0
customers = "YYYY"
4
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Solve Minimum Penalty for a Shop — You are given the customer visit log of a shop represented by a 0-indexed string...
Here's the optimal approach using String:
Time: O(n) | Space: O(n)
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