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Given a function fn, return a memoized version of that function. A memoized function is a function that will never be called twice with the same inputs. Instead it will return a cached value. fn can be any function and there are no constraints on what type of values it accepts. Inputs are considered identical if they are === to each other.
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Given a function fn, return a memoized version of that function. A memoized function is a function that will never be called twice with the same inputs. Instead it will return a cached value. fn can be any function and there are no constraints on what type of values it accepts. Inputs are considered identical if they are === to each other.
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getInputs = () => [[2,2],[2,2],[1,2]] fn = function (a, b) { return a + b; }[{"val":4,"calls":1},{"val":4,"calls":1},{"val":3,"calls":2}]getInputs = () => [[{},{}],[{},{}],[{},{}]] fn = function (a, b) { return ({...a, ...b}); }[{"val":{},"calls":1},{"val":{},"calls":2},{"val":{},"calls":3}]getInputs = () => { const o = {}; return [[o,o],[o,o],[o,o]]; } fn = function (a, b) { return ({...a, ...b}); }[{"val":{},"calls":1},{"val":{},"calls":1},{"val":{},"calls":1}]Reinforce undetectability, platform compatibility, and real-time assistance to remove any doubt.
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Solve Memoize II — Given a function fn, return a memoized version of that function. A memoized func...
Here's the optimal approach using the right algorithm:
Time: O(n) | Space: O(n)
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