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A string is a valid parentheses string (denoted VPS) if and only if it consists of "(" and ")" characters only, and: We can similarly define the nesting depth depth(S) of any VPS S as follows: For example, "", "()()", and "()(()())" are VPS's (with nesting depths 0, 1, and 2), and ")(" and "(()" are not VPS's. Given a VPS seq, split it into two disjoint subsequences A and B, such that A and B are VPS's (and A.length + B.length = seq.length). Now choose any such A and B such that max(depth(A), depth(B)) is the minimum possible value. Return an answer array (of length seq.length) that encodes such a choice of A and B: answer[i] = 0 if seq[i] is part of A, else answer[i] = 1. Note that even though multiple answers may exist, you may return any of them.
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A string is a valid parentheses string (denoted VPS) if and only if it consists of "(" and ")" characters only, and: We can similarly define the nesting depth depth(S) of any VPS S as follows: For example, "", "()()", and "()(()())" are VPS's (with nesting depths 0, 1, and 2), and ")(" and "(()" are not VPS's. Given a VPS seq, split it into two disjoint subsequences A and B, such that A and B are VPS's (and A.length + B.length = seq.length). Now choose any such A and B such that max(depth(A), depth(B)) is the minimum possible value. Return an answer array (of length seq.length) that encodes such a choice of A and B: answer[i] = 0 if seq[i] is part of A, else answer[i] = 1. Note that even though multiple answers may exist, you may return any of them.
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seq = "(()())"
[0,1,1,1,1,0]
seq = "()(())()"
[0,0,0,1,1,0,1,1]
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Solve Maximum Nesting Depth of Two Valid Parentheses Strings — A string is a valid parentheses string (denoted VPS) if and only if it consists ...
Here's the optimal approach using String:
Time: O(n) | Space: O(n)
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