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A magical string s consists of only '1' and '2' and obeys the following rules: The first few elements of s is s = "1221121221221121122……". If we group the consecutive 1's and 2's in s, it will be "1 22 11 2 1 22 1 22 11 2 11 22 ......" and the occurrences of 1's or 2's in each group are "1 2 2 1 1 2 1 2 2 1 2 2 ......". You can see that the occurrence sequence is s itself. Given an integer n, return the number of 1's in the first n number in the magical string s.
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A magical string s consists of only '1' and '2' and obeys the following rules: The first few elements of s is s = "1221121221221121122……". If we group the consecutive 1's and 2's in s, it will be "1 22 11 2 1 22 1 22 11 2 11 22 ......" and the occurrences of 1's or 2's in each group are "1 2 2 1 1 2 1 2 2 1 2 2 ......". You can see that the occurrence sequence is s itself. Given an integer n, return the number of 1's in the first n number in the magical string s.
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n = 6
3
n = 1
1
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Solve Magical String — A magical string s consists of only '1' and '2' and obeys the following rules: T...
Here's the optimal approach using Two Pointers:
Time: O(n) | Space: O(n)
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