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Given a list of strings words and a string pattern, return a list of words[i] that match pattern. You may return the answer in any order. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word. Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.
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Given a list of strings words and a string pattern, return a list of words[i] that match pattern. You may return the answer in any order. A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word. Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.
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words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb"
["mee","aqq"]
words = ["a","b","c"], pattern = "a"
["a","b","c"]
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Solve Find and Replace Pattern — Given a list of strings words and a string pattern, return a list of words[i] th...
Here's the optimal approach using Array:
Time: O(n) | Space: O(n)
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