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How to Solve Find All People With Secret Problem
Master the Find All People With Secret LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.
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Start Free for WindowsHard#2092
LeetCode ProblemFind All People With Secret
You are given an integer n indicating there are n people numbered from 0 to n - 1. You are also given a 0-indexed 2D integer array meetings where meetings[i] = [xi, yi, timei] indicates that person xi and person yi have a meeting at timei. A person may attend multiple meetings at the same time. Finally, you are given an integer firstPerson. Person 0 has a secret and initially shares the secret with a person firstPerson at time 0. This secret is then shared every time a meeting takes place with a person that has the secret. More formally, for every meeting, if a person xi has the secret at timei, then they will share the secret with person yi, and vice versa. The secrets are shared instantaneously. That is, a person may receive the secret and share it with people in other meetings within the same time frame. Return a list of all the people that have the secret after all the meetings have taken place. You may return the answer in any order.
Depth-First SearchBreadth-First SearchUnion FindGraphSorting
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Problem Breakdown
Understanding the Find All People With Secret Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
You are given an integer n indicating there are n people numbered from 0 to n - 1. You are also given a 0-indexed 2D integer array meetings where meetings[i] = [xi, yi, timei] indicates that person xi and person yi have a meeting at timei. A person may attend multiple meetings at the same time. Finally, you are given an integer firstPerson. Person 0 has a secret and initially shares the secret with a person firstPerson at time 0. This secret is then shared every time a meeting takes place with a person that has the secret. More formally, for every meeting, if a person xi has the secret at timei, then they will share the secret with person yi, and vice versa. The secrets are shared instantaneously. That is, a person may receive the secret and share it with people in other meetings within the same time frame. Return a list of all the people that have the secret after all the meetings have taken place. You may return the answer in any order.
HardProblem #2092
LeetCodeFind All People With Secret
Related Topics
Depth-First SearchBreadth-First SearchUnion FindGraphSorting
How Phantom Code Helps
Get real-time assistance for Find All People With Secret problems during coding interviews. Phantom Code provides instant solutions and explanations.
Examples
# Example 1
Input
n = 6, meetings = [[1,2,5],[2,3,8],[1,5,10]], firstPerson = 1
Output
[0,1,2,3,5]
# Example 2
Input
n = 4, meetings = [[3,1,3],[1,2,2],[0,3,3]], firstPerson = 3
Output
[0,1,3]
# Example 3
Input
n = 5, meetings = [[3,4,2],[1,2,1],[2,3,1]], firstPerson = 1
Output
[0,1,2,3,4]
Constraints
2 <= n <= 105
1 <= meetings.length <= 105
meetings[i].length == 3
0 <= xi, yi <= n - 1
xi != yi
1 <= timei <= 105
1 <= firstPerson <= n - 1
How Phantom Code Helps with LeetCode Problems
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Solve Find All People With Secret — You are given an integer n indicating there are n people numbered from 0 to n - ...
Here's the optimal approach using Depth-First Search:
def solve(input):
# Optimal O(n) solution
return result
Time: O(n) | Space: O(n)
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Frequently Asked Questions
Common questions about solving Find All People With Secret and using Phantom Code during coding interviews.
How does Phantom Code help me solve coding problems like Find All People With Secret during interviews?
Phantom Code generates complete solutions instantly with proper complexity analysis, letting you focus on explaining your approach and demonstrating problem-solving skills rather than getting stuck on implementation details during high-pressure situations.
What if the interviewer asks follow-up questions or modifications to problems like Find All People With Secret?
Phantom Code adapts in real-time. Screenshot the modified problem or use audio mode to capture the interviewer's follow-up, and get an updated solution within seconds — including edge cases and optimizations.
Can Phantom Code help me communicate my solution for problems like Find All People With Secret?
Yes. Phantom Code provides step-by-step approach explanations with 3 progressive thoughts, so you can walk through your solution naturally. It also provides time and space complexity analysis to discuss trade-offs.
How does Phantom Code assist with different programming languages for Find All People With Secret type problems?
Phantom Code supports 11 programming languages including Python, Java, C++, JavaScript, TypeScript, Go, Rust, Ruby, Swift, Kotlin, and C#. Set your preferred language and get idiomatic solutions.
What coding mistakes does Phantom Code help me avoid during Find All People With Secret interviews?
Phantom Code catches common mistakes like off-by-one errors, missing edge cases, incorrect base conditions, and suboptimal approaches. It provides clean, well-structured code that handles all edge cases.
Is Phantom Code detectable when solving problems like Find All People With Secret during live interviews?
No. Phantom Code runs as an invisible desktop overlay that doesn't appear in screen shares, recordings, or proctoring software. It works with Zoom, HackerRank, CodeSignal, CoderPad, and all major platforms.
How does Phantom Code help when I'm struggling with Find All People With Secret style questions under pressure?
The AI provides structured guidance: first the approach (what algorithm/data structure to use and why), then the implementation with clean code, and finally complexity analysis. This helps you think clearly even under pressure.
Does Phantom Code work for the coding platforms used in Find All People With Secret interviews?
Yes. Phantom Code works with all major coding platforms including LeetCode, HackerRank, CodeSignal, CoderPad, HackerEarth, and any browser-based coding environment.
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