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A string s can be partitioned into groups of size k using the following procedure: Note that the partition is done so that after removing the fill character from the last group (if it exists) and concatenating all the groups in order, the resultant string should be s. Given the string s, the size of each group k and the character fill, return a string array denoting the composition of every group s has been divided into, using the above procedure.
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A string s can be partitioned into groups of size k using the following procedure: Note that the partition is done so that after removing the fill character from the last group (if it exists) and concatenating all the groups in order, the resultant string should be s. Given the string s, the size of each group k and the character fill, return a string array denoting the composition of every group s has been divided into, using the above procedure.
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s = "abcdefghi", k = 3, fill = "x"
["abc","def","ghi"]
s = "abcdefghij", k = 3, fill = "x"
["abc","def","ghi","jxx"]
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Solve Divide a String Into Groups of Size k — A string s can be partitioned into groups of size k using the following procedur...
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Time: O(n) | Space: O(n)
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