Master the Count Paths That Can Form a Palindrome in a Tree LeetCode problem with undetectable real-time assistance. Get instant solutions and explanations during your coding interviews.
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You are given a tree (i.e. a connected, undirected graph that has no cycles) rooted at node 0 consisting of n nodes numbered from 0 to n - 1. The tree is represented by a 0-indexed array parent of size n, where parent[i] is the parent of node i. Since node 0 is the root, parent[0] == -1. You are also given a string s of length n, where s[i] is the character assigned to the edge between i and parent[i]. s[0] can be ignored. Return the number of pairs of nodes (u, v) such that u < v and the characters assigned to edges on the path from u to v can be rearranged to form a palindrome. A string is a palindrome when it reads the same backwards as forwards.
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You are given a tree (i.e. a connected, undirected graph that has no cycles) rooted at node 0 consisting of n nodes numbered from 0 to n - 1. The tree is represented by a 0-indexed array parent of size n, where parent[i] is the parent of node i. Since node 0 is the root, parent[0] == -1. You are also given a string s of length n, where s[i] is the character assigned to the edge between i and parent[i]. s[0] can be ignored. Return the number of pairs of nodes (u, v) such that u < v and the characters assigned to edges on the path from u to v can be rearranged to form a palindrome. A string is a palindrome when it reads the same backwards as forwards.
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parent = [-1,0,0,1,1,2], s = "acaabc"
8
parent = [-1,0,0,0,0], s = "aaaaa"
10
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Solve Count Paths That Can Form a Palindrome in a Tree — You are given a tree (i.e. a connected, undirected graph that has no cycles) roo...
Here's the optimal approach using Dynamic Programming:
Time: O(n) | Space: O(n)
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