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You are given a 2D integer array rectangles where rectangles[i] = [li, hi] indicates that ith rectangle has a length of li and a height of hi. You are also given a 2D integer array points where points[j] = [xj, yj] is a point with coordinates (xj, yj). The ith rectangle has its bottom-left corner point at the coordinates (0, 0) and its top-right corner point at (li, hi). Return an integer array count of length points.length where count[j] is the number of rectangles that contain the jth point. The ith rectangle contains the jth point if 0 <= xj <= li and 0 <= yj <= hi. Note that points that lie on the edges of a rectangle are also considered to be contained by that rectangle.
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You are given a 2D integer array rectangles where rectangles[i] = [li, hi] indicates that ith rectangle has a length of li and a height of hi. You are also given a 2D integer array points where points[j] = [xj, yj] is a point with coordinates (xj, yj). The ith rectangle has its bottom-left corner point at the coordinates (0, 0) and its top-right corner point at (li, hi). Return an integer array count of length points.length where count[j] is the number of rectangles that contain the jth point. The ith rectangle contains the jth point if 0 <= xj <= li and 0 <= yj <= hi. Note that points that lie on the edges of a rectangle are also considered to be contained by that rectangle.
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rectangles = [[1,2],[2,3],[2,5]], points = [[2,1],[1,4]]
[2,1]
rectangles = [[1,1],[2,2],[3,3]], points = [[1,3],[1,1]]
[1,3]
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Solve Count Number of Rectangles Containing Each Point — You are given a 2D integer array rectangles where rectangles[i] = [li, hi] indic...
Here's the optimal approach using Array:
Time: O(n) | Space: O(n)
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