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You are given an m x n binary grid, where each 1 represents a brick and 0 represents an empty space. A brick is stable if: You are also given an array hits, which is a sequence of erasures we want to apply. Each time we want to erase the brick at the location hits[i] = (rowi, coli). The brick on that location (if it exists) will disappear. Some other bricks may no longer be stable because of that erasure and will fall. Once a brick falls, it is immediately erased from the grid (i.e., it does not land on other stable bricks). Return an array result, where each result[i] is the number of bricks that will fall after the ith erasure is applied. Note that an erasure may refer to a location with no brick, and if it does, no bricks drop.
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You are given an m x n binary grid, where each 1 represents a brick and 0 represents an empty space. A brick is stable if: You are also given an array hits, which is a sequence of erasures we want to apply. Each time we want to erase the brick at the location hits[i] = (rowi, coli). The brick on that location (if it exists) will disappear. Some other bricks may no longer be stable because of that erasure and will fall. Once a brick falls, it is immediately erased from the grid (i.e., it does not land on other stable bricks). Return an array result, where each result[i] is the number of bricks that will fall after the ith erasure is applied. Note that an erasure may refer to a location with no brick, and if it does, no bricks drop.
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grid = [[1,0,0,0],[1,1,1,0]], hits = [[1,0]]
[2]
grid = [[1,0,0,0],[1,1,0,0]], hits = [[1,1],[1,0]]
[0,0]
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Solve Bricks Falling When Hit — You are given an m x n binary grid, where each 1 represents a brick and 0 repres...
Here's the optimal approach using Array:
Time: O(n) | Space: O(n)
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